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WB JEE Medical WB JEE Medical Solved Paper-2011

  • question_answer
    If g is the acceleration due to gravity on the surface of the earth, the gain in potential energy of an object of mass m raised from the earths surface to a height equal to the radius R of the earth is

    A)  \[\frac{mgR}{4}\]                           

    B)  \[\frac{mgR}{2}\]

    C)  \[mgR\]                              

    D)  \[2mgR\]

    Correct Answer: B

    Solution :

                     The potential energy on the surface of earth would be equal to \[mgR.\] So, the change in potential energy would be equal to \[\Delta PE=\frac{mgh}{1+\frac{h}{R}}=\frac{mgR}{1+\frac{R}{R}}=\frac{mgR}{2}\]


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