WB JEE Medical WB JEE Medical Solved Paper-2011

  • question_answer
    A material has Poissons ratio 0.50. If a uniform rod of it suffers a longitudinal strain of \[2\times {{10}^{-3}},\] then the percentage change in volume is

    A)  0.6                                        

    B)  0.4

    C)  0.2                                        

    D)  zero

    Correct Answer: D

    Solution :

                     Given that the material has a Poissons ratio is 0.50 and the longitudinal strain of \[2\times {{10}^{-3}}.\] Now the Poissons ratio is defined as\[v=-\frac{d{{\varepsilon }_{trans}}}{d{{\varepsilon }_{axial}}}=-\frac{d{{\varepsilon }_{y}}}{d{{\varepsilon }_{x}}}=-\frac{d{{\varepsilon }_{z}}}{d{{\varepsilon }_{x}}}\]where v is the resulting Poissons ratio, is transverse strain [negative for axial tension (stretching), positive for axial compression] is  axial strain (positive for axial tension, negative for axial compression). Thus there is no change in volume.


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