WB JEE Medical WB JEE Medical Solved Paper-2011

  • question_answer
    An object weights \[{{m}_{1}}\]in a liquid of density \[{{d}_{1}}\]and that in liquid of density \[{{d}_{2}}\]is \[{{m}_{2}}.\]density d of the object is

    A)  \[\frac{{{m}_{2}}{{d}_{2}}-{{m}_{1}}{{d}_{1}}}{{{m}_{2}}-{{m}_{1}}}\]                    

    B)  \[\frac{{{m}_{1}}{{d}_{1}}-{{m}_{2}}{{d}_{2}}}{{{m}_{2}}-{{m}_{1}}}\]

    C)  \[\frac{{{m}_{2}}{{d}_{1}}-{{m}_{1}}{{d}_{2}}}{{{m}_{1}}-{{m}_{2}}}\]                    

    D)  \[\frac{{{m}_{1}}{{d}_{2}}-{{m}_{2}}{{d}_{1}}}{{{m}_{1}}-{{m}_{2}}}\]

    Correct Answer: D

    Solution :

                     Given that an object weighs \[{{m}_{1}}\]in a liquid of density \[{{d}_{1}}\]and \[{{m}_{2}}\] in a liquid of density\[{{d}_{2}},\]  so when the density of the object is d, then we get \[V(d-{{d}_{1}})={{m}_{1}}\]                 And        \[V(d-{{d}_{2}})={{m}_{2}}\]                 Thus,                     \[\frac{d-{{d}_{1}}}{d-{{d}_{2}}}=\frac{{{m}_{1}}}{{{m}_{2}}}\]                 So, we get    \[\frac{{{m}_{1}}{{d}_{2}}-{{m}_{2}}{{d}_{1}}}{{{m}_{1}}-{{m}_{2}}}.\]


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