A) \[2\pi \sqrt{\frac{l}{g\,\cos \,\alpha }}\]
B) \[2\pi \sqrt{\frac{l}{g\,\sin \,\alpha }}\]
C) \[2\pi \sqrt{\frac{l}{g\,}}\]
D) \[2\pi \sqrt{\frac{l}{g\,\tan \,\alpha }}\]
Correct Answer: A
Solution :
We are given that the simple pendulum of length I is hanging from the roof of a vehicle which is moving down the frictionless inclined plane. So, its acceleration is \[g\,\sin \theta .\]Since vehicle is accelerating a pseudo force \[m(g\,sin\theta )\] will act on bob of pendulum which cancel the \[\sin \,\theta \]component of weight of the bob.You need to login to perform this action.
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