WB JEE Medical WB JEE Medical Solved Paper-2011

  • question_answer
    A plane progressive wave is given by \[y=2\cos 6.284(330t-x).\]What is period of the wave?

    A)  \[\frac{1}{330}s\]                           

    B)  \[2\pi \times 330\,s\]

    C)  \[{{(2\pi \times 330)}^{-1}}s\]  

    D)  \[\frac{6.284}{330}s\]

    Correct Answer: A

    Solution :

                      We have the progressive wave given by \[y=2\,\cos \,6.284(330\,t-x)=2\cos 2\pi (330t-x)\] \[=2\,\cos (2\pi \times 330t-2\pi x).\]     \[\omega =2\pi \times 330,\] and time period \[T=\frac{2\pi }{\omega }=\frac{1}{330}s.\]


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