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WB JEE Medical WB JEE Medical Solved Paper-2011

  • question_answer
    If the focal length of the eye-piece of a telescope is doubled, its magnifying power (m) will be

    A)  \[2\,m\]                                             

    B)  \[3\,m\]

    C)  \[\frac{m}{2}\]                                

    D)  \[4m\]

    Correct Answer: C

    Solution :

                     We know the magnifying power (m) is given by \[m=-\frac{{{f}_{o}}}{{{f}_{e}}}.\]Now if the focal length of the Ie eye-piece \[({{f}_{e}})\] is doubled, then the new magnification   would   be   equal   to \[m=-\frac{{{f}_{o}}}{2{{f}_{e}}}=\frac{m}{2}\]


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