A) \[-0.35\,V\]
B) \[+\,0.35\text{ }V\]
C) \[+1.17\,V\]
D) \[-1.17\,V\]
Correct Answer: B
Solution :
\[Zn\xrightarrow{{}}Z{{n}^{2+}}+2{{e}^{-}};E_{oxi}^{o}=+0.76\,V\]or \[E_{red}^{o}=-0.76\,V\] \[Fe\xrightarrow{{}}F{{e}^{2+}}2{{e}^{-}};E_{oxi}^{o}=+0.41\,V\] or \[E_{red}^{o}=-0.41\,V\] \[\therefore \] \[E_{cell}^{o}=E_{cathode}^{o}(RP)-E_{anode}^{o}(RP)\] \[=-0.41-(0.76)\] \[=+\,0.35\,V\]You need to login to perform this action.
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