A) \[HO-\underset{H}{\overset{H}{\mathop{\underset{|}{\overset{|}{\mathop{C-C{{O}_{2}}H}}}\,}}}\,\]
B) \[{{H}_{3}}C-\underset{OH}{\overset{H}{\mathop{\underset{|}{\overset{|}{\mathop{C-C{{O}_{2}}H}}}\,}}}\,\]
C) \[{{H}_{3}}C-\underset{H}{\overset{C\,{{H}_{3}}}{\mathop{\underset{|}{\overset{|}{\mathop{C-C{{O}_{2}}H}}}\,}}}\,\]
D) \[{{H}_{3}}C-\underset{Cl}{\overset{C\,{{H}_{3}}}{\mathop{\underset{|}{\overset{|}{\mathop{C-C{{O}_{2}}H}}}\,}}}\,\]
Correct Answer: B
Solution :
2-hydroxypropanoic acid has a central carbon atom, which is linked to four different groups. This carbon atom is called chiral carbon atom and the molecule is called chiral molecule. Hence, 2-hydroxy propanoic acid shows optical isomerism.
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