A) \[-100\,x\,\text{kJ/mol}\]
B) \[-50\,x\,\text{kJ/mol}\]
C) \[+\,100\,x\,\text{kJ/mol}\]
D) \[+50\,x\,\text{kJ/mol}\]
Correct Answer: A
Solution :
Millimoles (or milliequivalents) of\[NaOH=20\times 0.5=10\] Millimoles (or milliequivalents) of \[HCl=100\times 0.1=10\] \[\therefore \]\[\underset{10}{\mathop{NaOH}}\,+\underset{10}{\mathop{HCl}}\,\to NaCl+{{H}_{2}}O\]milliequivalents milliequivalents Thus, heat released when 10 milliequivalents of HCl are neutralised by 10 millimoles of \[NaOH=x\,kJ.\]But heat of neutralisation is heat released when 1 equivalent of HCl is neutralised by 1 equivalent of NaOH. \[\therefore \] \[{{\Delta }_{neu}}H=-\frac{x}{10\times 10}\]or \[-100x\,\text{kJ/mol}\]
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