A) 50
B) 100
C) 150
D) 200
Correct Answer: D
Solution :
As 2 g of metal carbonate is neutralised by 100 mL of 0.1 N HCl. \[\because \] Number of gram-equivalents of HCl \[=\frac{100\times 0.1}{1000}\] \[=0.01\] \[\therefore \]Number of gram-equivalents of metal carbonate = 0.01 Mass of 0.01 gram equivalent metal carbonate = 2 g Mass of 1 gram equivalent metal carbonate \[=\frac{2}{0.01}\] \[=200\,g\] \[\therefore \]Equivalent mass of metal carbonate = 200
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