question_answer

If the molecular wt. of \[\text{N}{{\text{a}}_{\text{2}}}{{\text{S}}_{\text{2}}}{{\text{O}}_{\text{3}}}\]and \[{{\text{I}}_{\text{2}}}\] are \[{{\text{M}}_{1}}\]and \[{{\text{M}}_{2}}\]respectively then what will be the equivalent weight of \[\text{N}{{\text{a}}_{\text{2}}}{{\text{S}}_{\text{2}}}{{\text{O}}_{\text{3}}}\]and \[{{\text{I}}_{2}}\]in the following reaction? \[2{{S}_{2}}O_{3}^{2-}+{{I}_{2}}\xrightarrow{{}}{{S}_{4}}O_{6}^{2-}+2{{I}^{-}}\]

A)  \[{{M}_{1}},{{M}_{2}}\]                               

B)  \[{{M}_{1}},{{M}_{2}}/2\]

C)  \[2{{M}_{1}},{{M}_{2}}\]                            

D)  \[{{M}_{1}}2{{M}_{2}}\]

Correct Answer: B

Solution :

                  \[\therefore \]Equivalent mass of \[{{S}_{2}}O_{3}^{2-}=\frac{{{M}_{1}}}{1}={{M}_{1}}\] and equivalent mass of \[{{I}_{2}}=\frac{{{M}_{2}}}{2}\]