A) \[X-4-Y\]
B) \[X-Y-5\]
C) \[X-Y-3\]
D) \[X-Y-6\]
Correct Answer: B
Solution :
An\[\alpha -\]emission reduces the atomic mass by 4 and atomic number by 2, whereas a \[\beta -\]emission increases the atomic number by 1 with no change in atomic mass. \[M_{Y}^{X}\xrightarrow{-\alpha }N_{Y-2}^{X-4}\xrightarrow{-\alpha }O_{Y-4}^{X-8}\xrightarrow{-\beta }P_{Y-3}^{X-8}\] Number of neutrons = mass number - atomic number \[=X-8-Y+3\] \[=X-Y-5\]
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