A) 0.11
B) 0.13
C) 0.15
D) 1.2
Correct Answer: B
Solution :
Given that \[1.56\times {{10}^{5}}\,J\]of heat is conducted through a \[2{{m}^{2}}\] wall having a thickness of 12 cm in a time interval of 1 h. Hence, we have \[\frac{dQ}{dt}=\frac{KA\Delta T}{x}\] Thus, we get \[\frac{1.56\times {{10}^{5}}}{1\times 60\times 60}=\frac{K\times 2\times 20}{12\times {{10}^{-2}}}\] So, \[K=\frac{1.56\times {{10}^{5}}\times 12\times {{10}^{-12}}}{1\times 60\times 60\times 2\times 20}=\frac{1.56}{12}=0.13\]You need to login to perform this action.
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