A) \[\text{Mn}{{\text{O}}_{2}}\]
B) \[{{H}_{2}}S\]
C) \[KMn{{O}_{4}}\]
D) \[C{{r}_{2}}{{O}_{3}}\]
Correct Answer: C
Solution :
\[2KMn{{O}_{4}}+16HCl\xrightarrow{{}}2KCl+2MnC{{l}_{2}}\]\[+8{{H}_{2}}O+5C{{l}_{2}}\]
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