A) 2.678 N
B) 5.336 N
C) 8.034 N
D) 6.685 N
Correct Answer: B
Solution :
Volume strength \[=5.6\times \]normality Or normally \[\text{=}\frac{\text{volume}\,\text{strength}}{\text{5}\text{.6}}\]\[=\frac{30}{5.6}=5.35\,N\]
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