A) \[6{{y}^{4}}\]
B) \[36{{y}^{4}}\]
C) \[64{{y}^{5}}\]
D) \[108{{y}^{5}}\]
Correct Answer: D
Solution :
\[C{{a}_{3}}{{(P{{O}_{4}})}_{2}}(s)\underset{3y}{\mathop{3C{{a}^{2+}}}}\,(q)+\underset{2y}{\mathop{2PO_{4}^{3-}}}\,(aq)\] \[\therefore \] \[{{K}_{sp}}={{[C{{a}^{2+}}]}^{3}}.{{[PO_{4}^{3-}]}^{2}}\] \[={{(3y)}^{3}}.{{(2y)}^{2}}\] \[=27{{y}^{3}}\times 4{{y}^{2}}\] \[=108{{y}^{5}}\]
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