A) \[\frac{3V}{R}\]
B) \[\frac{V}{R}\]
C) \[\frac{V}{2R}\]
D) \[\frac{2V}{R}\]
Correct Answer: C
Solution :
The effective figure can be given by From the wheat stone bridge balance, we get \[\frac{R}{R}=\frac{R}{R}=1\] Hence, no current flows through the central resistance C. Thus, the effective resistance is equal to \[\frac{1}{{{R}_{eff}}}=\frac{1}{(R+R)}+\frac{1}{(R+R)}=\frac{1}{2R}+\frac{1}{2R}=\frac{1}{R}\] Hence, \[{{R}_{eff}}=R\] Now, the current \[I=\frac{V}{R},\]hence the current through FC would be equal to \[\frac{I}{2}=\frac{V}{2R}.\]You need to login to perform this action.
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