A) 3 mA
B) 6 mA
C) 12 mA
D) 36 Ma
Correct Answer: A
Solution :
From KCL we have \[i=\frac{72}{8\times {{10}^{3}}}=9\times {{10}^{-3}}A\] \[i=\frac{72}{8\times {{10}^{3}}}=9\times {{10}^{-3}}A\] \[i=3\,mA\]You need to login to perform this action.
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