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WB JEE Medical WB JEE Medical Solved Paper-2012

  • question_answer
    A progressive wave moving along \[x-\]axis is represented by y\[y=A\,\sin \left[ \frac{2\pi }{\lambda }(vt-x) \right].\] The wavelength \[(\lambda )\] at which the maximum particle velocity is 3 times the wave velocity is

    A)  \[A/3\]

    B)  \[2A/(3\pi )\]

    C)  \[\left( \frac{3}{4} \right)\pi A\]

    D)  \[(2/3)\pi A\]

    Correct Answer: D

    Solution :

     \[y=A\sin \left[ \frac{2\pi }{\lambda }(vt-x) \right]\] \[v=\frac{2\pi }{\lambda }VA\] \[{{({{v}_{p}})}_{\max }}=3v\] \[\lambda =\frac{2\pi }{3}A\]


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