2. Solved Papers
  3. WB JEE Medical

WB JEE Medical WB JEE Medical Solved Paper-2012

  • question_answer
    Which of the following is correct?

    A)  Radius of \[C{{a}^{2+}}<C{{l}^{-}}<{{S}^{2-}}\]

    B)  Radius of \[C{{l}^{-}}<{{S}^{2-}}<C{{a}^{2+}}\]

    C)  Radius of \[{{S}^{2-}}=C{{l}^{-}}=C{{a}^{2+}}\]

    D)  Radius of \[{{S}^{2-}}<C{{l}^{-}}<C{{a}^{2+}}\]

    Correct Answer: A

    Solution :

    Species Atomic Number Number of electrons
    \[C{{a}^{2+}}\] 20 \[20-2=18\]
    \[C{{l}^{-}}\] 17 \[17+1=18\]
    \[{{S}^{2-}}\] 16 \[16+2=18\]
    For isoelectronic species, an increase in atomic number, result in decreased size. Thus, order of radius will be \[C{{a}^{2+}}<C{{l}^{-}}<{{S}^{2-}}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner