question_answer

What current will flow through the \[2\,k\Omega \] resistor in the circuit shown in the figure?

A)  3 mA 

B)  6 mA

C)  12 mA

D)  36 Ma

Correct Answer: A

Solution :

 From KCL we have \[i=\frac{72}{8\times {{10}^{3}}}=9\times {{10}^{-3}}A\] \[i=\frac{72}{8\times {{10}^{3}}}=9\times {{10}^{-3}}A\] \[i=3\,mA\]