A) M/3
B) M/4
C) M/6
D) M/7
Correct Answer: C
Solution :
In acidic medium, \[{{K}_{2}}\overset{+\,6}{\mathop{C{{r}_{2}}}}\,{{O}_{7}}\xrightarrow{{}}C{{r}^{3+}}\] Equivalent weight of \[{{K}_{2}}C{{r}_{2}}{{O}_{7}}=\frac{\text{Molecular}\,\text{weight}}{\text{Change}\,\text{in}\,\text{oxidation}\,\text{state}\,\text{of}\,\text{Cr}}\] \[=\frac{M}{2(6-3)}=\frac{M}{6}\]You need to login to perform this action.
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