A) 0.5
B) 1.0
C) 2.0
D) 3.0
Correct Answer: A
Solution :
Given \[v=3\times {{10}^{8}}m{{s}^{-1}},d=10\,m\]and \[\mu =1.5\] Here, \[t=\frac{d}{c/\mu }\] \[t=\frac{10\times {{10}^{-2}}}{2\times {{10}^{8}}}\] \[\left( \because \,\frac{c}{\mu }=\frac{3\times {{10}^{8}}}{1.5}=2\times {{10}^{8}}m{{s}^{-1}} \right)\] \[t=0.5\times {{10}^{-9}}s\]You need to login to perform this action.
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