A) \[\sigma /{{\varepsilon }_{0}}\]towards the positively charged plane
B) \[\sigma /{{\varepsilon }_{0}}\]towards the negatively charged plane
C) \[\sigma /(2{{\varepsilon }_{0}})\]towards the positively charged plane
D) 0 and towards any direction
Correct Answer: B
Solution :
\[E=\frac{\sigma }{2{{\varepsilon }_{0}}}+\frac{\sigma }{2{{\varepsilon }_{0}}}\] \[E=\frac{\sigma }{{{\varepsilon }_{0}}}\]towards negative charged plate.You need to login to perform this action.
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