A) \[E/\sqrt{2}\]
B) \[E/2\]
C) \[E/4\]
D) \[E/8\]
Correct Answer: C
Solution :
At ground, \[E=\frac{1}{3}m{{u}^{2}}\] At highest point,\[E=\frac{1}{2}m{{(u\,cos{{60}^{o}})}^{2}}\] \[E=\frac{E}{4}\]You need to login to perform this action.
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