question_answer

An equimolar mixture of toluene and chlorobenzene is treated with a mixture of cone. \[{{H}_{2}}S{{O}_{4}}\]and cone. \[HN{{O}_{3}}.\]Indicate the correct statement from the following.

A)  p-nitrotoluene is formed in excess

B)  equimolar amounts of p-nitrotoluene and p-nitrochlorobenzene are formed

C)  p-nitrochlorobenzene is formed in excess

D)  m-nitrochlorobenzene is formed in excess

Correct Answer: A

Solution :

  As toluene and chlorobenzene, both can react with mixture of cone. \[{{H}_{2}}S{{O}_{4}}\]and cone. \[HN{{O}_{3}},\]but being more reactive, toluene will yield p-nitrotoluene in excess.