A) 1.0 A
B) 0.2 A
C) 0.1 A
D) 2.0 A
Correct Answer: B
Solution :
Effective resistance, \[{{R}_{eff}}=\frac{40\times 120}{120+40}=\frac{4800}{160}=30\,\Omega \] \[\therefore \]Current \[I=\frac{7}{(30+5)}=\frac{7}{35}=0.2A\] \[\left[ \because \,I=\frac{E}{R+r} \right]\]You need to login to perform this action.
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