A) 5cm
B) 2.5cm
C) 1.67cm
D) 1.5cm
Correct Answer: C
Solution :
Given \[{{P}_{1}}=40D,\]and\[{{P}_{2}}=20D\] We have \[{{P}_{eff}}=40D+20D=60D\] \[\Rightarrow \] \[f=\frac{100}{{{P}_{eff}}}=\frac{100}{60}\] \[=1.67\,cm\]You need to login to perform this action.
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