A) HCI
B) KOH
C) \[C{{O}_{2}}\]
D) \[S{{O}_{2}}\]
Correct Answer: D
Solution :
Since,\[O{{H}^{-}}\] are generated from weak acid \[({{H}_{2}}O),\] a weak acid (like\[C{{O}_{2}}\]) should be used to remove it because of strong acid (HCI) reverse the reaction. KOH increases the concentration of \[O{{H}^{-}},\]thus again shifts the reaction in backward side. \[C{{O}_{2}}\]combines with \[O{{H}^{-}}\]to give carbonate which is easily removed. \[S{{O}_{2}}\]reacts with water to give strong acid, so it cannot be used.You need to login to perform this action.
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