A) 9J
B) 6J
C) 13 J
D) 15 J
Correct Answer: A
Solution :
Given, force \[F=3i+j\] \[{{r}_{1}}=(2i+k)m\]and \[{{r}_{2}}=(4i+3j-k)m\] \[\therefore \] \[s={{r}_{2}}-{{r}_{1}}=(4i+3j-k)-(2i+k)\] \[=(2i+3j-2k)m\] \[\therefore \] \[W=F.s=(3i+j).(2i+3j-2k)\] \[=3\times 2+3+0\] \[=6+3=9J\]You need to login to perform this action.
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