A) \[0.2\,\Omega \]
B) \[0.5\,\Omega \]
C) \[0.8\,\Omega \]
D) \[1.0\,\Omega \]
Correct Answer: B
Solution :
\[l=\frac{E}{R+r}\] or \[E=l(R+r)\] \[2.1=0.2(10+r)\] \[10+r=\frac{2.1}{2}\times 10\] \[\therefore \] \[r=10.5-10=0.5\,\Omega \]You need to login to perform this action.
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