WB JEE Medical WB JEE Medical Solved Paper-2013

  • question_answer
    A stone falls freely under gravity. It covers distances \[{{h}_{1}},{{h}_{2}}\]and \[{{h}_{3}}\]in the first 5 seconds, the next 5 seconds and the next 5 seconds respectively. The relation between \[{{h}_{1}},{{h}_{2}}\]and \[{{h}_{3}}\] is

    A) \[{{h}_{1}}=2{{h}_{2}}=3{{h}_{3}}\]

    B)  \[{{h}_{1}}=\frac{{{h}_{2}}}{3}=\frac{{{h}_{3}}}{{{h}_{5}}}\]

    C)  \[{{h}_{2}}=3{{h}_{1}}\] and \[{{h}_{3}}=3{{h}_{2}}\]

    D) \[{{h}_{1}}={{h}_{2}}={{h}_{3}}\]

    Correct Answer: B

    Solution :

     The relation between \[{{h}_{1}},{{h}_{2}}\] and\[{{h}_{3}}\] is \[{{h}_{1}}=\frac{h}{3}=\frac{{{h}_{3}}}{5}\] \[\Rightarrow \] \[{{h}_{1}}:{{h}_{2}}:{{h}_{3}}=1:3:5\]


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