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WB JEE Medical WB JEE Medical Solved Paper-2013

  • question_answer
     A certain mass of hydrogen is changed to helium by the process of fusion. The mass defect in fusion reaction is 0.02866 u. The energy liberated, per u is (given 1 u =931 MeV)

    A)  2.67 MeV       

    B)  26.7 MeV

    C)  6.675 MeV      

    D)  13.35MeV

    Correct Answer: C

    Solution :

     Here,\[\Delta m=0.02866\,U\] \[\therefore \] Energy liberated \[=\frac{0.02866\times 931}{4}=\frac{26.7}{4}\,MeV=6.675\,MeV\]


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