A) 8,500 yr
B) 9,200 yr
C) 10,000 yr
D) 11. 000 yr
Correct Answer: B
Solution :
Age of archaeological sample, \[t=\frac{2.303}{k}\log \left( \frac{{{N}_{0}}}{N} \right)\] (Here, \[{{N}_{0}}=\]initial activity, N = remaining activity) and \[k=\frac{0.693}{{{t}_{1/2}}}\] (where \[{{t}_{1/2}}=\] half-life) \[=\frac{0.693}{5770}Y{{r}^{-1}}\] \[\therefore \] \[t=\frac{2.303\times 5770}{0.693}\log \left( \frac{15}{5} \right)\] \[=19175.0\log 3\,Yr\] \[=9148\,Yr\approx 9200\,Yr\]You need to login to perform this action.
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