A) \[{{H}_{3}}P{{O}_{2}}\]
B) \[{{H}_{3}}P{{O}_{3}}\]
C) \[{{H}_{3}}P{{O}_{4}}\]
D) \[NaHS{{O}_{3}}\]
Correct Answer: A
Solution :
\[{{\text{H}}_{\text{3}}}\text{P}{{\text{O}}_{\text{2}}}\]is the reagent that converts \[-N_{2}^{+}C{{l}^{-}}\] group into H. During this process \[{{N}_{2}}\]and\[HCl\] gases are released.
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