A) \[HgS{{O}_{4}}/dil.{{H}_{2}}S{{O}_{4}}\]
B) \[B{{H}_{3}};{{H}_{2}}{{O}_{2}}/NaOH\]
C) \[Os{{O}_{4}};HI{{O}_{4}}\]
D) \[NaN{{H}_{2}}/C{{H}_{3}}l;HgS{{O}_{4}}/dil.{{H}_{2}}S{{O}_{4}}\]
Correct Answer: D
Solution :
(Here, Me means methyl group) Thus, the correct set of reagents is \[NaN{{H}_{2}}/C{{H}_{3}}I;HgS{{O}_{4}}/dil\,{{H}_{2}}S{{O}_{4}}.\]You need to login to perform this action.
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