A) \[\frac{y-2x}{2}\]
B) \[y+2x\]
C) \[2x-y\]
D) \[\frac{2x-y}{2}\]
Correct Answer: A
Solution :
Given, \[C+{{O}_{2}}\xrightarrow{{}}C{{O}_{2}};\Delta {{H }^{o}}=-x\,kJ\] ?(i) \[2CO+{{O}_{2}}\xrightarrow{{}}2C{{O}_{2}};{{H}^{o}}=-Y\,kJ\] ?(ii) Required equation is \[C+\frac{1}{2}{{O}_{2}}\xrightarrow{{}}CO;\Delta H _{1}^{o}=?\] On reversing eq. (ii), we get \[2C{{O}_{2}}\xrightarrow{{}}2CO+{{O}_{2}};\Delta H_{2}^{o}=+Y\,kJ\] ?(iii) Dividing eq. (iii) by 2 gives \[C{{O}_{2}}\xrightarrow{{}}CO+\frac{1}{2}{{O}_{2}};\Delta H_{3}^{o}=+\frac{Y}{2}\,kJ\] ?(iv) On adding eq. (i) and (iv), we get (required equation) \[C+\frac{1}{2}{{O}_{2}}\xrightarrow{{}}CO;\Delta H_{1}^{o}=\Delta {{H}^{o}}+\Delta H_{3}^{o}\] \[=\left( -x\frac{y}{2} \right)\,kJ\] \[=\frac{y-2x}{2}\,kJ\]You need to login to perform this action.
You will be redirected in
3 sec