A) 24
B) 30
C) 40
D) 60
Correct Answer: D
Solution :
The combination of three charges in series \[\frac{1}{C}=\frac{1}{{{C}_{1}}}+\frac{1}{{{C}_{1}}}+\frac{1}{{{C}_{3}}}\] \[\frac{1}{C}=\frac{1}{3}+\frac{1}{6}+\frac{1}{6}\]\[\Rightarrow \]\[C=\frac{6}{4}=1.5\mu F\] The charge of this circuit \[q=CV=1.5\times 120\] \[q=180\mu C\] The potential difference across the \[3\mu F\] \[q=CV\] \[V=\frac{q}{C}=\frac{180}{3}=60\,V\]You need to login to perform this action.
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