A) \[4.2\,\,\times {{10}^{3}}\]
B) \[3.0\,\,\times {{10}^{3}}\]
C) \[1.2\,\,\times \,\,{{10}^{3}}\]
D) \[1.5\,\,\times \,{{10}^{3}}\]
Correct Answer: D
Solution :
Given, \[305\,X-25X=100{{\,}^{o}}C\] (\[\because \] X is the new unit of temperature) \[(305-25)X=100{{\,}^{o}}C\Rightarrow 280X=100{{\,}^{o}}C\] \[\therefore \] \[1{{\,}^{o}}C=2.8x\] The specific heat capacity of water \[=4200\frac{\text{joule}}{\text{kg}{{\,}^{\text{o}}}\text{C}}=4200\times \frac{\text{joule}}{\text{kg }\!\!\times\!\!\text{ 2}\text{.8x}}\] \[=1500\,J/kg-x\] \[=1.5\times {{10}^{3}}J\,k{{g}^{-1}}{{x}^{-1}}\]You need to login to perform this action.
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