A) area
B) length
C) speed
D) acceleration
Correct Answer: A
Solution :
\[\left[ \frac{nh}{2\pi qB} \right]\] where n and \[2\pi \] dimensionless quantity So, \[[h]=[mvr]\] \[[qB]=\left[ \frac{qvB}{v} \right]=\left[ \frac{F}{v} \right]\] \[\therefore \] \[\left[ \frac{mvr}{F/v} \right]=\frac{[mvr][v]}{[F]}\] \[=\frac{[m{{v}^{2}}r]}{\left[ \frac{m{{v}^{2}}}{r} \right]}=[{{r}^{2}}]=Area\]You need to login to perform this action.
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