A) \[\frac{v}{r(\pi -2)}\]
B) \[\frac{v}{r(\pi -1)}\]
C) \[\frac{2v}{r(\pi -1)}\]
D) \[\frac{v}{r(\pi +1)}\]
Correct Answer: A
Solution :
Path difference \[=(\pi r-2r)\] \[=(\pi -2)r=n\lambda \](where\[f=\]frequency) \[v=f\times \lambda \] \[\Rightarrow \] \[\frac{v}{\lambda }=f\Rightarrow f=\left[ \frac{v}{(\pi -2)r} \right]n\] So, multiples integral\[=\left[ \frac{v}{(\pi -2)r} \right]\]You need to login to perform this action.
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