A) 2 g
B) 0.5 g
C) 1 g
D) 0.75 g
Correct Answer: C
Solution :
Elevation of boiling point, \[\Delta {{\Tau }_{b}}=\frac{w\times {{K}_{b}}\times 1000}{M\times W}\] (Here, w and W = weights of solute and solvent respectively, M = molecular weight of solute and \[{{K}_{b}}=\]constant) On substituting values, we get \[0.05=\frac{w\times 0.5\times 1000}{100\times 100}\] or \[w=\frac{0.05\times 100\times 100}{0.5\times 1000}=1g\]You need to login to perform this action.
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