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WB JEE Medical WB JEE Medical Solved Paper-2014

  • question_answer
    A galvanometer having internal resistance \[10\,\Omega \] requires 0.01 A for a full scale deflection. To  convert this galvanometer to a voltmeter of full-scale deflection at 120 V, we need to connect a resistance of

    A)  \[11990\,\Omega \]in series

    B)  \[11990\,\Omega \]in parallel

    C) \[12010\,\Omega \] in series

    D)  \[12010\,\Omega \]in parallel

    Correct Answer: A

    Solution :

     Resistance \[R=\frac{V}{{{i}_{g}}}-G=\frac{120}{0.01}-10\]\[=12000-10\] \[R=11990\,\Omega \] To convert a galvanometer into a voltmeter, high resistance should connect in series.


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