question_answer

In the circuit shown assume the diode to be ideal. When \[{{V}_{i}}\]increases from 2V to 6 V, the change in the current is (in mA)

A)  zero

B)  20

C)  \[80/3\]

D)  40

Correct Answer: B

Solution :

 \[{{I}_{\operatorname{initial}}}=0,\] \[{{I}_{final}}=\frac{3}{150}=0.02\,A\] So, change in \[I=0.02\,A=20\,mA\]