A) inversely proportional to \[\alpha \]
B) inversely proportional to \[\gamma \]
C) directly proportional to \[\Delta T/\gamma \]
D) independent of L
Correct Answer: C
Solution :
Strain \[=\alpha .\Delta T\] Stress \[Y\propto \Delta \Tau \] where L = length of the rod \[\alpha =\]coefficient of linear thermal expansion \[Y=\]Youngs modulus of its material So, the longitudinal stress developed in the rod is directly proportional to\[\frac{\Delta T}{Y}.\]You need to login to perform this action.
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