A) 60 min
B) 30 min
C) 45 min
D) 15min
Correct Answer: B
Solution :
According to Grahams law of diffusion, Rate of diffusion, \[r\propto \frac{1}{\sqrt{M}}=\frac{V}{t}\] [Here, M = molecular mass, V = volume and t = time] Thus, for \[{{H}_{2}}\]gas, \[\frac{200}{30}=\frac{1}{\sqrt{2}}\] ?(i) For \[{{\text{O}}_{\text{2}}}\]gas, \[\frac{50}{t}=\frac{1}{\sqrt{32}}\] ?(ii) From Eqs. (i) and (ii), we get \[\frac{200\times t}{30\times 50}=\frac{\sqrt{32}}{\sqrt{2}}\] \[t=\frac{\sqrt{16}\times 30\times 50}{200}\] \[=\frac{4\times 30}{4}=30\,\text{min}\]
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