A) \[{{m}_{2}},({{m}_{1}}>{{m}_{2}})\]
B) \[\frac{{{({{m}_{1}}-{{m}_{2}})}^{2}}}{{{m}_{1}}+{{m}_{2}}}g\]
C) \[({{m}_{1}}-{{m}_{2}})g\]
D) \[\frac{{{({{m}_{1}}+{{m}_{2}})}^{2}}}{{{m}_{1}}-{{m}_{2}}}g\]
Correct Answer: B
Solution :
We know that Acceleration, \[{{a}_{CM}}={{\left( \frac{{{m}_{1}}-{{m}_{2}}}{{{m}_{1}}+{{m}_{2}}} \right)}^{2}}\times g\,\] \[(\because \,{{m}_{_{1}}}>{{m}_{2}})\] So, resultant external force, \[F=({{m}_{1}}+{{m}_{2}}){{a}_{CM}}\] \[=({{m}_{1}}+{{m}_{2}})\times {{\left( \frac{{{m}_{1}}-{{m}_{2}}}{{{m}_{1}}+{{m}_{2}}} \right)}^{2}}\times g\] \[=\frac{{{({{m}_{1}}-{{m}_{2}})}^{2}}}{({{m}_{1}}+{{m}_{2}})}\times g\]You need to login to perform this action.
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