A) \[\frac{w}{{{w}_{1}}}\]
B) \[\frac{w{{l}_{1}}}{wl-{{w}_{1}}{{l}_{2}}}\]
C) \[\frac{{{l}_{1}}}{{{l}_{1}}-{{l}_{2}}}\]
D) \[\frac{{{l}_{1}}}{{{l}_{2}}}\]
Correct Answer: C
Solution :
\[Wl={{W}_{1}}{{l}_{1}}\] ?(i) where \[\rho =\] specific gravity \[Wl\left( 1-\frac{1}{\rho } \right)={{W}_{1}}{{l}_{2}}\] \[\left( 1-\frac{1}{\rho } \right)=\frac{{{W}_{1}}{{l}_{2}}}{Wl}\] [from Eq. (ii)] \[\left( 1-\frac{1}{\rho } \right)=\frac{{{W}_{1}}{{l}_{2}}}{{{W}_{1}}{{l}_{1}}}\] \[1-\frac{1}{\rho }=\frac{{{l}_{2}}}{{{l}_{1}}}\Rightarrow \frac{1}{\rho }=1-\frac{{{l}_{2}}}{{{l}_{1}}}\] \[\frac{1}{\rho }=\frac{{{l}_{1}}-{{l}_{2}}}{{{l}_{1}}}\]or \[\rho =\frac{{{l}_{1}}}{{{l}_{1}}-{{l}_{2}}}\]You need to login to perform this action.
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