A) the energy stored in the capacitor decreases
B) the capacitance of the capacitor increases
C) the charge on the capacitor decreases
D) the voltage across the capacitor increases
Correct Answer: D
Solution :
We know that The parallel plate capacitor \[C=\frac{{{\varepsilon }_{0}}.A}{d}\] When d (distance between two parallel plate) increase, then C will be decrease \[\because \] \[Q=CV\]where \[Q=\] constant \[\therefore \] The voltage across the capacitor increases.
You need to login to perform this action.
You will be redirected in
3 sec
