A) changes periodically with a frequency of v
B) changes periodically with a frequency of 2v
C) changes periodically with a frequency of \[v/2\]
D) remains constant
Correct Answer: B
Solution :
We know that Kinetic energy \[K=\frac{1}{2}m{{u}^{2}}\] where\[u=\frac{dy}{dt}=\omega a\,\cos \omega t\] So, \[K=\frac{1}{2}m{{\omega }^{2}}{{a}^{2}}\,{{\cos }^{2}}\omega t\] Hence, kinetic energy varies periodically with double the frequency of SHM. So, when a particle executing SHM oscillates with a frequency v, then the kinetic energy of particle changes periodically with a frequency of 2v.
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